A 100.0 g block of metal absorbs 750 J as it warms from 25.0 °C to 50.0 °C.
What is the specific heat of the metal?
- A
0.030 J/g·°C
- Bcheck_circle
0.300 J/g·°C
- C
3.00 J/g·°C
- D
0.500 J/g·°C
Explanation
c = q/(mΔT) = 750/(100.0 · 25.0) = 0.300 J/g·°C.
Heat Capacity and Calorimetry
AP Chemistry· difficulty 3/5
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