For HO(l) → HO(g) at 100°C with ΔH = 40.7 kJ/mol, ΔS is approximately
- Acheck_circle
+109 J/(mol·K) (ΔS = ΔH/T at equilibrium)
- B
+1090 J/(mol·K)
- C
-109 J/(mol·K)
- D
+40.7 J/(mol·K)
Explanation
At equilibrium (boiling point), ΔG = 0, so ΔS = ΔH/T = 40700/373 = 109 J/(mol·K).