Electrolysis and Faraday's Law

AP Chemistry· difficulty 3/5

A current of 5.00 A is run through a Ag⁺ solution for 1 hour.

I = 5.00 A, t = 3600 s Ag⁺ + e⁻ → Ag (108 g/mol) Find mass Ag

What mass of Ag is deposited?

  • A

    40.3 g

  • B

    10.1 g

  • C

    20.1 g

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  • D

    5.04 g

Explanation

Q = 5.00·3600 = 18000 C. mol e⁻ = 18000/96485 = 0.1866. mol Ag = 0.1866. mass = 0.1866·108 = 20.15 g.

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