A student titrates 25.00 mL of 0.100 M acetic acid with 0.100 M NaOH while monitoring pH. Selected pH values: at 0.00 mL added, pH = 2.87; at 12.50 mL (half-equivalence), pH = 4.74; at 25.00 mL (equivalence), pH = 8.72.
Why is the equivalence pH greater than 7?
- A
Excess NaOH is present at equivalence
- Bcheck_circle
The solution at equivalence is sodium acetate, whose acetate ion hydrolyzes to give OH-
- C
All titration equivalence points are basic
- D
Acetic acid is a strong acid
Explanation
At equivalence the solution contains the salt of a weak acid (NaCH3COO). The acetate ion is a weak base (CH3COO- + H2O <-> CH3COOH + OH-), giving pH > 7.