For a reaction at four temperatures, k values are determined and ln k is plotted vs 1/T. The slope of the best-fit line is −1.20×10⁴ K.
What is the activation energy Eₐ?
- A
8.31 kJ/mol
- Bcheck_circle
99.7 kJ/mol
- C
144 kJ/mol
- D
12.0 kJ/mol
Explanation
Eₐ = −R(slope) = −(8.314 J/mol·K)(−1.20×10⁴ K) = 9.98×10⁴ J/mol ≈ 99.7 kJ/mol.