For N₂ + 3H₂ ⇌ 2NH₃ (Kc = 0.50 at T), a vessel contains [N₂] = 1.0 M, [H₂] = 1.0 M, [NH₃] = 1.0 M.
What is Q, and which way does the reaction shift?
- A
Q = 0.50; system at equilibrium.
- B
Q = 2.0; shifts left.
- C
Q = 1.0; shifts right.
- Dcheck_circle
Q = 1.0; shifts left (reverse).
Explanation
Q = [NH₃]²/([N₂][H₂]³) = 1²/(1·1³) = 1.0. Q > Kc, so reverse.