AP Chemistry· difficulty 4/5
A concentration cell uses Ag electrodes in 0.10 M Ag⁺ (cathode) and 1.0×10⁻⁴ M Ag⁺ (anode) at 25 °C.
What is E_cell?
0.00 V
−0.18 V
+0.18 V
+0.059 V
Explanation
E = (0.0592/1) log([Ag⁺]_cath/[Ag⁺]_an) = 0.0592 · log(0.10/1×10⁻⁴) = 0.0592 · 3 = 0.178 V ≈ +0.18 V.
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