For PbCl₂ ⇌ Pb²⁺ + 2 Cl⁻, K_sp =
- A
[Pb²⁺]²[Cl⁻]
- B
[PbCl₂]/[Pb²⁺][Cl⁻]
- Ccheck_circle
[Pb²⁺][Cl⁻]²
- D
[Pb²⁺][Cl⁻]
Explanation
Solid omitted; product of ion concentrations to coefficients.
AP Chemistry· difficulty 2/5
For PbCl₂ ⇌ Pb²⁺ + 2 Cl⁻, K_sp =
[Pb²⁺]²[Cl⁻]
[PbCl₂]/[Pb²⁺][Cl⁻]
[Pb²⁺][Cl⁻]²
[Pb²⁺][Cl⁻]
Explanation
Solid omitted; product of ion concentrations to coefficients.
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