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Henderson-Hasselbalch Equation

AP Chemistry· difficulty 3/5

A buffer is prepared with 0.20 M acetic acid (Ka = 1.8×10⁻⁵) and 0.20 M sodium acetate.

Component Concentration (M) CH₃COOH 0.20 CH₃COO⁻ 0.20 Ka = 1.8×10⁻⁵

What is the pH?

  • A

    7.00

  • B

    4.74

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  • C

    9.26

  • D

    5.00

Explanation

pH = pKa + log([A⁻]/[HA]) = -log(1.8×10⁻⁵) + log(1) = 4.74 + 0 = 4.74.

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