For the reaction , mixing 4.0 mol H with 3.0 mol O produces how many mol HO?
- A
6.0 mol
- B
7.0 mol
- C
3.0 mol (O limiting)
- Dcheck_circle
4.0 mol (H limiting, 2:2 ratio)
Explanation
H needs 2.0 mol O; we have 3.0 mol so O is in excess. H limiting → 4.0 mol HO (2 H : 2 HO ratio).