For 2 H₂ + O₂ → 2 H₂O: starting from 8.0 g of H₂, the mass of H₂O produced (excess O₂) is
- A
16 g
- Bcheck_circle
72 g
- C
36 g
- D
8 g
Explanation
8.0 g / 2 g·mol⁻¹ = 4 mol H₂ → 4 mol H₂O × 18 g/mol = 72 g.
AP Chemistry· difficulty 3/5
For 2 H₂ + O₂ → 2 H₂O: starting from 8.0 g of H₂, the mass of H₂O produced (excess O₂) is
16 g
72 g
36 g
8 g
Explanation
8.0 g / 2 g·mol⁻¹ = 4 mol H₂ → 4 mol H₂O × 18 g/mol = 72 g.
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