Representations of Solutions

AP Chemistry· difficulty 3/5

A student needs 500 mL of 1.0 M H₂SO₄ from 6.0 M stock. Volume of stock required:

  • A

    300 mL

  • B

    166 mL

  • C

    83 mL

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  • D

    8.3 mL

Explanation

M₁V₁ = M₂V₂: V₁ = (1.0 × 500)/6.0 ≈ 83 mL.

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