To prepare 1.0 L of 0.10 M KCl, you need _______ g of KCl. (M(KCl) = 74.5)
- Acheck_circle
7.45
- B
0.745
- C
10
- D
74.5
Explanation
0.10 mol × 74.5 g/mol = 7.45 g, dissolved and diluted to 1.0 L.
Representations of Solutions
AP Chemistry· difficulty 2/5
Want 10 more like this — adaptive to your weak spots?