Calculate E^\circ{cell} for Zn + Cu^{2+} \rightarrow Zn^{2+} + Cu given E^\circ(Zn^{2+}/Zn) = -0.76 V and E^\circ(Cu^{2+}/Cu) = +0.34 V.

E^\circ{cell} = +1.10 V E^\circ{cell} = E^\circ{cathode} - E^\circ{anode} = 0.34 - (-0.76) = +1.10 V. Spontaneous since positive.

Cell Potential and Free Energy

AP Chemistry· difficulty 4/5

E^\circ_{cell}

Explanation

E^\circ_{cell}

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