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Absolute Entropy and Entropy Change

AP Chemistry· difficulty 4/5

Calculate ΔS∘\Delta S^\circ for 2H2(g)+O2(g)→2H2O(g)2H_2(g) + O_2(g) \rightarrow 2H_2O(g) given S∘S^\circ: H2H_2 = 130.7, O2O_2 = 205.2, H2O(g)H_2O(g) = 188.8 J/mol·K.

  • A

    +89.0+89.0 J/K

  • B

    −147.0-147.0 J/K

  • C

    −44.5-44.5 J/K

  • D

    −89.0-89.0 J/K

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Explanation

ΔS∘\Delta S^\circ = 2(188.8) - [2(130.7) + 205.2] = 377.6 - 466.6 = −89.0-89.0 J/K. Negative because moles of gas decrease (3 →\rightarrow 2).

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