Gibbs Free Energy and Thermodynamic Favorability

AP Chemistry· difficulty 4/5

For a reaction at 298 K: ΔH\Delta H = +25.0 kJ/mol, ΔS\Delta S = +120 J/mol·K. At what temperature does the reaction become spontaneous?

  • A

    T<208T < 208 K

  • B

    T>298T > 298 K

  • C

    T>208T > 208 K

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  • D

    Always spontaneous

Explanation

ΔG\Delta G = 0 when T = ΔH/ΔS\Delta H/\Delta S = 25000/120 = 208 K. Above 208 K, TΔS>ΔHT\Delta S > \Delta H, so ΔG<0\Delta G < 0 (spontaneous).

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