VSEPR and Bond Hybridization

AP Chemistry· difficulty 4/5

SF₄ has the molecular geometry

A
$Square planar$
B
$Seesaw (trigonal bipyramidal electron geometry, one equatorial lone pair)$
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C
$Octahedral$
D
$Tetrahedral with no lone pairs$

Explanation

S has 6 valence e⁻; 4 bond pairs to F + 1 lone pair = 5 e⁻ domains \to trigonal bipyramidal. Lone pair occupies an equatorial site (less repulsion) \to seesaw shape.

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