Properties of Buffers

AP Chemistry· difficulty 3/5

CH3COOH/CH3COO- buffer pKa = 4.74 pH = pKa + log([A-]/[HA]) [A-]/[HA] = 1 -> pH = ?

What is the pH when the conjugate base/acid ratio = 1?

  • A

    7.00

  • B

    4.74

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  • C

    9.26

  • D

    5.74

Explanation

log(1) = 0, so pH = pKa = 4.74.

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