A buffer contains 0.20 M HF and 0.30 M NaF. The pH is (Ka(HF) = 7.2 imes10^{-4}, \log 7.2 = 0.86)

Question

A buffer contains 0.20 M HF and 0.30 M NaF. The pH is (Ka(HF) = 7.2	imes10^{-4}, \log 7.2 = 0.86)

Accepted Answer

3.32 (pKa + \log([F^-]/[HF]))

pH = pKa + \log([F^-]/[HF]) = -\log(7.2	imes10^{-4}) + \log(0.30/0.20) = 3.143 + 0.176 = 3.32.

Answer

3.14

Answer

3.44

Answer

3.32 (pKa + \log([F^-]/[HF]))

Answer

10.86

Properties of Buffers