pH and pOH of Strong Acids and Bases

AP Chemistry· difficulty 2/5

Solution has [OH-] = 1.0e-3 M.

0 7 14 pH 14 7 0 pOH pH + pOH = 14 (at 25 C)

What is pH?

  • A

    3

  • B

    11

    check_circle
  • C

    7

  • D

    14

Explanation

pOH = -log(1e-3) = 3. pH = 14 - 3 = 11.

Want 10 more like this — adaptive to your weak spots?

Related questions