AP Chemistry · Topic 8.2

pH and pOH of Strong Acids and Bases Practice

Part of Acids and Bases.(SAP-9.B)

Practice questions

11

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Sample questions

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  1. Sample 1difficulty 1/5

    pH =

    • A

      ln[H⁺]

    • B

      −log[H⁺]

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    • C

      [H⁺]

    • D

      log[H⁺]

    Why

    pH = −log[H⁺] (or −log a_H⁺ rigorously).

  2. Sample 2difficulty 2/5

    0.0010 M NaOH [OH-] = 0.0010 M pOH = 3 pH = ?

    What is pH?

    • A

      13

    • B

      10

    • C

      3

    • D

      11

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    Why

    pH = 14 - pOH = 14 - 3 = 11.

  3. Sample 3difficulty 2/5

    0.010 M HCl(aq) [H+] = 0.010 M pH = -log[H+] pH = ?

    What is the pH?

    • A

      12.0

    • B

      2.0

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    • C

      0.010

    • D

      1.0

    Why

    HCl is a strong acid, so [H+] = 0.010 M, and pH = -log(0.010) = 2.0.

  4. Sample 4difficulty 2/5

    pH of 0.010 M NaOH is

    • A

      7.0

    • B

      12.0

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    • C

      2.0

    • D

      14.0

    Why

    [OH⁻] = 0.010 → pOH = 2 → pH = 12.

  5. Sample 5difficulty 2/5

    Solution has [OH-] = 1.0e-3 M.

    0 7 14 pH 14 7 0 pOH pH + pOH = 14 (at 25 C)

    What is pH?

    • A

      3

    • B

      11

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    • C

      7

    • D

      14

    Why

    pOH = -log(1e-3) = 3. pH = 14 - 3 = 11.