Use a galvanic cell with Sn|Sn²⁺ and Ag|Ag⁺.
What is E°cell?
- Acheck_circle
+0.94 V
- B
-0.94 V
- C
+0.66 V
- D
+0.80 V
Explanation
Cathode = Ag⁺/Ag (+0.80 V), anode = Sn²⁺/Sn (-0.14 V): E°cell = +0.80 - (-0.14) = +0.94 V.
Cell Potential and Free Energy
AP Chemistry· difficulty 4/5
Want 10 more like this — adaptive to your weak spots?
Related questions
- chem-hard4-023
Calculate E^\circ{cell} for Zn + Cu^{2+} \rightarrow Zn^{2+} + Cu given E^\circ(Zn^{2+}/Zn) = -0.76 V and E^\circ(Cu^{2+}/Cu) = +0.34 V.…
chevron_right - chem-ec-009
A galvanic (spontaneous) cell has…
chevron_right - chem-ec-032
Adding more Cu²⁺ to a Zn–Cu cell at standard conditions causes E to…
chevron_right