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Cell Potential Under Nonstandard Conditions

AP Chemistry· difficulty 4/5

A Daniell cell at standard conditions has E° = +1.10 V. If [Cu2+^{2+}] is decreased and [Zn2+^{2+}] increased, the cell potential

  • A

    Decreases below 1.10 V (Q increases, −log⁡Q-\log Q becomes negative)

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  • B

    Increases above 1.10 V

  • C

    Becomes negative

  • D

    Stays at 1.10 V

Explanation

Q=[Zn2+]/[Cu2+]Q = [Zn^{2+}]/[Cu^{2+}]. Increasing this raises Q. E=E°−(0.0592/2)log⁡QE = E° − (0.0592/2)\log Q — bigger Q means E decreases.

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