Vaporize 36.0 g H₂O at 100°C → steam at 100°C. ΔHvap = 40.7 kJ/mol.
How much heat is required?
- Acheck_circle
+81.4 kJ
- B
+22.6 kJ
- C
+40.7 kJ
- D
+1466 kJ
Explanation
n = 36.0/18.0 = 2.00 mol; q = (2.00)(40.7) = 81.4 kJ.
Energy of Phase Changes
AP Chemistry· difficulty 4/5
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