Heating 18 g water from −10 °C ice to +10 °C liquid (c_ice ≈ 2.0, c_liq = 4.18 J/g·°C; ΔH_fus = 6.0 kJ/mol). Total q ≈
- A
18 kJ
- B
1.5 kJ
- C
0.4 kJ
- Dcheck_circle
7.4 kJ
Explanation
Warm ice: 18·2.0·10 = 360 J. Melt: 6000 J. Warm water: 18·4.18·10 ≈ 752 J. Total ≈ 7.1 kJ ≈ 7.4 kJ.