For A + B -> P with rate = k[A][B], [B] is held in large excess. ln[A] vs t is linear.
The observed rate constant k_obs equals:
- A
k/[B]0
- B
k/[A]0
- C
k
- Dcheck_circle
k[B]0
Explanation
With [B] ≈ [B]0 constant, rate = k[B]0[A] = k_obs[A], so k_obs = k[B]0.