Introduction to Rate Law

AP Chemistry· difficulty 3/5

With rate = k[A]² and [A]=0.1 M giving rate=4×10⁻³ M/s, k =

  • A

    0.4 s⁻¹

  • B

    4 M⁻¹·s⁻¹

  • C

    0.04 M⁻¹·s⁻¹

  • D

    0.4 M⁻¹·s⁻¹

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Explanation

k = rate/[A]² = 4×10⁻³/0.01 = 0.4 M⁻¹·s⁻¹.

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