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Introduction to Rate Law

AP Chemistry· difficulty 3/5

Initial rates for X -> products are recorded.

Trial [X] M Rate (M/s) 1 0.10 0.0050 2 0.20 0.0100 3 0.30 0.0150

What is the order with respect to X and the value of k?

  • A

    1st order; k = 0.10 s^-1

  • B

    2nd order; k = 0.050 M^-1 s^-1

  • C

    Zero order; k = 0.0050 M/s

  • D

    1st order; k = 0.050 s^-1

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Explanation

Rate doubles when [X] doubles -> 1st order. k = rate/[X] = 0.0050/0.10 = 0.050 s^-1.

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