For N + 3H ⇌ 2 NH, K = 0.50 at 400°C. If [N]=1.0, [H]=2.0, [NH]=0.50, the system
- A
Shifts left (Q > K)
- B
Is at equilibrium
- C
Cannot be determined
- Dcheck_circle
Shifts right (Q < K)
Explanation
Q = [NH]/([N][H]) = (0.50)/((1.0)(2.0)) = 0.25/8 = 0.031. Q < K (0.031 < 0.50), so reaction shifts right toward products.