For 2 A ⇌ B with [A]₀ = 1.0 M, [B]₀ = 0, K_c = 0.50. At equilibrium, [A] is
- A
1.00 M
- Bcheck_circle
0.69 M
- C
0.50 M
- D
0.80 M
Explanation
K = x/(1−2x)² = 0.5; solving x ≈ 0.155 → [A] ≈ 1 − 2(0.155) ≈ 0.69 M.
Calculating Equilibrium Concentrations
AP Chemistry· difficulty 4/5
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