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Cell Potential and Free Energy

AP Chemistry· difficulty 4/5

For a cell with n=2n = 2 and E°=+1.10E° = +1.10 V, ΔG° is approximately (F=96500F = 96500 C/mol)

  • A

    −106 kJ/mol

  • B

    +212 kJ/mol

  • C

    +1.10 kJ/mol

  • D

    −212 kJ/mol (−nFE°-nFE°)

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Explanation

ΔG° = −nFE°-nFE° = −(2)(96500)(1.10)-(2)(96500)(1.10) = −212,300-212{,}300 J/mol = −212-212 kJ/mol.

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