To deposit 1.08 g Ag (10 mmol) from Ag⁺ at 1.0 A, time required is approximately
- A
9650 s
- B
96485 s
- Ccheck_circle
965 s
- D
97 s
Explanation
Q = nF = 0.010 × 96485 ≈ 965 C; t = Q/I ≈ 965 s.
AP Chemistry· difficulty 4/5
To deposit 1.08 g Ag (10 mmol) from Ag⁺ at 1.0 A, time required is approximately
9650 s
96485 s
965 s
97 s
Explanation
Q = nF = 0.010 × 96485 ≈ 965 C; t = Q/I ≈ 965 s.
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