For 2 e⁻ transfer with E° = 1.10 V, ΔG° (kJ/mol) ≈
- A
−500
- B
+212
- Ccheck_circle
−212
- D
−110
Explanation
ΔG° = −2 × 96485 × 1.10 ≈ −212,000 J = −212 kJ.
AP Chemistry· difficulty 3/5
For 2 e⁻ transfer with E° = 1.10 V, ΔG° (kJ/mol) ≈
−500
+212
−212
−110
Explanation
ΔG° = −2 × 96485 × 1.10 ≈ −212,000 J = −212 kJ.
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