A compound contains 40.0% C, 6.7% H, and 53.3% O by mass. Its empirical formula is
- Acheck_circle
CH₂O
- B
C₆H₁₂O₆
- C
CHO
- D
C₂H₄O₂
Explanation
Divide by atomic mass: 40/12 ≈ 3.33, 6.7/1 = 6.7, 53.3/16 ≈ 3.33. Ratio 1:2:1 → CH₂O.
Elemental Composition of Pure Substances
AP Chemistry· difficulty 3/5
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