Which is a correct antiderivative of f(x)=cos(2x)f(x) = \cos(2x)f(x)=cos(2x)?A2sin(2x)2\sin(2x)2sin(2x)B−sin(2x)/2-\sin(2x)/2−sin(2x)/2Csin(2x)/2\sin(2x)/2sin(2x)/2check_circleD−2sin(2x)-2\sin(2x)−2sin(2x)ExplanationDifferentiate sin(2x)/2\sin(2x)/2sin(2x)/2: cos(2x)\cos(2x)cos(2x).