∫(x−2+x) dx=\int (x^{-2} + x)\,dx =∫(x−2+x)dx=Ax−1+x2/2+Cx^{-1} + x^2/2 + Cx−1+x2/2+CBln∣x∣+x2/2+C\ln|x| + x^2/2 + Cln∣x∣+x2/2+CC−x−1+x2/2+C-x^{-1} + x^2/2 + C−x−1+x2/2+Ccheck_circleDx3/3+x2/2+Cx^3/3 + x^2/2 + Cx3/3+x2/2+CExplanation∫x−2 dx=−x−1+C\int x^{-2}\,dx = -x^{-1} + C∫x−2dx=−x−1+C. ∫x dx=x2/2\int x\,dx = x^2/2∫xdx=x2/2.