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FTC and Definite Integrals

AP Calculus AB· difficulty 2/5

∫02(3−x) dx=\displaystyle\int_0^2 (3 - x)\,dx =

  • A

    33

  • B

    22

  • C

    55

  • D

    44

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Explanation

[3x−x2/2]02=6−2=4[3x - x^2/2]_0^2 = 6 - 2 = 4.

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