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Integration with Inverse Trig Functions

AP Calculus AB· difficulty 2/5

∫0111+x2 dx=\displaystyle\int_0^1 \dfrac{1}{1+x^2}\,dx =

  • A

    00

  • B

    π4\tfrac{\pi}{4}

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  • C

    π\pi

  • D

    π2\tfrac{\pi}{2}

Explanation

[arctan⁡x]01=π/4−0=π/4[\arctan x]_0^1 = \pi/4 - 0 = \pi/4.

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