AP Calculus AB · Topic 6.8

Integration with Inverse Trig Functions Practice

Part of Integration and Accumulation of Change.(FUN-6.C)

Practice questions

4

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Sample questions

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  1. Sample 1difficulty 2/5

    0111+x2dx=\displaystyle\int_0^1 \dfrac{1}{1+x^2}\,dx =

    • A

      00

    • B

      π4\tfrac{\pi}{4}

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    • C

      π\pi

    • D

      π2\tfrac{\pi}{2}

    Why

    [arctanx]01=π/40=π/4[\arctan x]_0^1 = \pi/4 - 0 = \pi/4.

  2. Sample 2difficulty 2/5

    11x2dx=\displaystyle\int \dfrac{1}{\sqrt{1-x^2}}\,dx =

    • A

      ln1x2+C\ln|1-x^2| + C

    • B

      arcsinx+C\arcsin x + C

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    • C

      arctanx+C\arctan x + C

    • D

      arccosx+C\arccos x + C

    Why

    arcsin(x)=1/1x2\arcsin'(x) = 1/\sqrt{1 - x^2}.

  3. Sample 3difficulty 2/5

    11+x2dx=\displaystyle\int \dfrac{1}{1 + x^2}\,dx =

    • A

      arcsinx+C\arcsin x + C

    • B

      arctanx+C\arctan x + C

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    • C

      ln(1+x2)+C\ln(1 + x^2) + C

    • D

      x21+x2+C\dfrac{x^2}{1+x^2} + C

    Why

    arctan(x)=1/(1+x2)\arctan'(x) = 1/(1+x^2).

  4. Sample 4difficulty 3/5

    14+x2dx=\displaystyle\int \dfrac{1}{4 + x^2}\,dx =

    • A

      14+x2+C\dfrac{1}{4 + x^2} + C

    • B

      12arctan(x/2)+C\dfrac{1}{2}\arctan(x/2) + C

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    • C

      14arctanx+C\dfrac{1}{4}\arctan x + C

    • D

      arctan(x/2)+C\arctan(x/2) + C

    Why

    Pattern 1/(a2+x2)1/(a^2 + x^2): antiderivative (1/a)arctan(x/a)(1/a)\arctan(x/a).