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The Chain Rule

AP Calculus AB· difficulty 4/5

ddxsin⁡(x2)\dfrac{d}{dx}\sin(x^2) at x=πx = \sqrt{\pi} is

  • A

    11

  • B

    00

  • C

    2π2\sqrt{\pi}

  • D

    −2π-2\sqrt{\pi}

    check_circle

Explanation

Chain: cos⁡(x2)⋅2x\cos(x^2)\cdot 2x. At x=πx=\sqrt{\pi}: cos⁡(π)⋅2π=−2π\cos(\pi) \cdot 2\sqrt{\pi} = -2\sqrt{\pi}.

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