ddx[(sinx)2]3=ddxsin6x=\dfrac{d}{dx}\bigl[(\sin x)^2\bigr]^3 = \dfrac{d}{dx}\sin^6 x =dxd[(sinx)2]3=dxdsin6x=A3sin2xcosx3\sin^2 x \cos x3sin2xcosxB6sin5xcosx6\sin^5 x \cos x6sin5xcosxcheck_circleCsin5x\sin^5 xsin5xD6sin5x6\sin^5 x6sin5xExplanation6sin5x⋅cosx6\sin^5 x \cdot \cos x6sin5x⋅cosx.