Position, Velocity, and Acceleration using Integrals

AP Calculus AB· difficulty 3/5

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Areas above and below axis are 10 and 7 respectively. Net displacement equals:

  • A

    33

    check_circle
  • B

    3-3

  • C

    1010

  • D

    1717

Explanation

Net displacement = signed area =107=3= 10 - 7 = 3.

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