With v(t)=2t+1v(t) = 2t + 1v(t)=2t+1 and s(0)=4s(0) = 4s(0)=4, find s(3)s(3)s(3).A131313B161616check_circleC101010D222222Explanations(t)=t2+t+Cs(t) = t^2 + t + Cs(t)=t2+t+C. s(0)=4=Cs(0) = 4 = Cs(0)=4=C. s(3)=9+3+4=16s(3) = 9 + 3 + 4 = 16s(3)=9+3+4=16.