Volumes with Cross Sections

AP Calculus AB· difficulty 3/5

For semicircular cross-sections perpendicular to the xx-axis with diameter equal to the base width w(x)w(x), the area of one cross-section is

  • A

    πw(x)\pi w(x)

  • B

    πw(x)22\dfrac{\pi w(x)^2}{2}

  • C

    πw(x)28\dfrac{\pi w(x)^2}{8}

    check_circle
  • D

    πw(x)2\pi w(x)^2

Explanation

Radius = w/2w/2. Semicircle area = 12πr2=πw28\tfrac{1}{2}\pi r^2 = \tfrac{\pi w^2}{8}.

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