Given g(2)=5g(2) = 5g(2)=5, g′(2)=3g'(2) = 3g′(2)=3, f′(5)=7f'(5) = 7f′(5)=7, find (f∘g)′(2)(f \circ g)'(2)(f∘g)′(2).A212121check_circleB101010C353535D151515Explanation(f∘g)′(2)=f′(g(2))⋅g′(2)=f′(5)⋅g′(2)=7⋅3=21(f \circ g)'(2) = f'(g(2)) \cdot g'(2) = f'(5) \cdot g'(2) = 7 \cdot 3 = 21(f∘g)′(2)=f′(g(2))⋅g′(2)=f′(5)⋅g′(2)=7⋅3=21.