ddxln(sinx)=\dfrac{d}{dx}\ln(\sin x) =dxdln(sinx)=Acosx\cos xcosxBcotx\cot xcotxcheck_circleCtanx\tan xtanxD1sinx\dfrac{1}{\sin x}sinx1Explanation1sinx⋅cosx=cotx\dfrac{1}{\sin x} \cdot \cos x = \cot xsinx1⋅cosx=cotx.