For f(x)=(4x+1)1/2f(x) = (4x + 1)^{1/2}f(x)=(4x+1)1/2, f′(2)=f'(2) =f′(2)=A23\tfrac{2}{3}32check_circleB13\tfrac{1}{3}31C16\tfrac{1}{6}61D46\tfrac{4}{6}64Explanationf′(x)=12(4x+1)−1/2⋅4=2/4x+1f'(x) = \tfrac{1}{2}(4x+1)^{-1/2}\cdot 4 = 2/\sqrt{4x+1}f′(x)=21(4x+1)−1/2⋅4=2/4x+1. At x=2x=2x=2: 2/32/32/3.