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Position, Velocity, and Acceleration using Integrals

AP Calculus AB· difficulty 2/5

Average velocity of v(t)=t2−2tv(t) = t^2 - 2t on [0,3][0, 3] is

  • A

    32\tfrac{3}{2}

  • B

    00

    check_circle
  • C

    11

  • D

    33

Explanation

13∫03(t2−2t) dt=(1/3)(9−9)=0\dfrac{1}{3}\int_0^3 (t^2 - 2t)\,dt = (1/3)(9 - 9) = 0.

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