L'Hôpital's Rule

AP Calculus AB· difficulty 2/5

\displaystyle\lim_{x\to 0}\dfrac{e^x - 1 - x}{x^2}

A
$1$
B
$\tfrac{1}{2}$
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C
$0$
D
$2$

Explanation

(e^x - 1)/(2x) \to e^x/2 \to 1/2

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