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L'Hôpital's Rule

AP Calculus AB· difficulty 3/5

Evaluate lim⁡x→0+xx\displaystyle\lim_{x\to 0^+} x^x.

  • A

    11

    check_circle
  • B

    ∞\infty

  • C

    ee

  • D

    00

Explanation

lim⁡xln⁡x=0\lim x \ln x = 0 (cal-cad-018), so xx=exln⁡x→e0=1x^x = e^{x\ln x} \to e^0 = 1.

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